Đáp án:
\(m_{\text{muối}}=84,75\ \text{gam}\)
Giải thích các bước giải:
\(n_{H_2}=\dfrac{14,56}{22,4}=0,65\ \text{mol}\)
\(\to n_{HCl}=2n_{H_2}=0,65\cdot 2=1,3\ \text{mol}\)
\(\to n_{Cl}=1,3\ \text{mol}\)
\(\to m_{Cl}=1,3\cdot 35,5=46,15\ \text{gam}\)
\(\to m_{\text{muối}}=38,6+46,15=84,75\ \text{gam}\)