Đáp án:
Giải thích các bước giải:
$a,\dfrac{16}{11}+\dfrac{3}{7}-\dfrac{5}{11}-\dfrac{6}{14}$
$=\left (\dfrac{16}{11}-\dfrac{5}{11} \right )+\left (\dfrac{3}{7}-\dfrac{6}{14} \right )$
$=1+\left (\dfrac{6}{14}-\dfrac{6}{14} \right )$
$=1$
$b,\dfrac{15}{16}.\dfrac{11}{7}-\dfrac{15}{16}.\dfrac{3}{7}$
$=\dfrac{15}{16}.\left (\dfrac{11}{7}-\dfrac{3}{7} \right )$
$=\dfrac{15}{16},\dfrac{8}{7}$
$=\dfrac{15}{14}$
$c,4.(-11).\dfrac{3}{4}.\dfrac{12}{132}$
$=\dfrac{1}{11}.(-11).4.\dfrac{3}{4}$
$=-1.3$
$=-3$
$d,\dfrac{1}{15}.\dfrac{-3}{11}-\dfrac{1}{15}:\dfrac{11}{8}$
$=\dfrac{1}{15}.\dfrac{-3}{11}-\dfrac{1}{15}.\dfrac{8}{11}$
$=\dfrac{1}{15}.\left (\dfrac{-3}{11}-\dfrac{8}{11} \right )$
$=\dfrac{1}{15}.(-1)$
$=-\dfrac{1}{15}$
$e,\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+\dfrac{2}{9.11}$
$=1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}$
$=1-\left (\dfrac{1}{3}-\dfrac{1}{3}+\dfrac{1}{5}-\dfrac{1}{5}+\dfrac{1}{7}-\dfrac{1}{7}+\dfrac{1}{9}-\dfrac{1}{9} \right ) -\dfrac{1}{11}$
$=1-\dfrac{1}{11}$
$=\dfrac{11}{11}-\dfrac{1}{11}$
$=\dfrac{10}{11}$
Chúc em học tốt . Cho xin câu trả lời hay nhất nha.
