Giải thích các bước giải:
a) `|x|+1/3+1/3+1/3=0`
`=>|x|+1=0`
`=>|x|=-1` $\text{(loại vì }|x|\geq0)$
b) `2/6+2/12+2/20+...+2/(x(x+1))=4/5`
`=>2(1/6+1/12+1/20+...+1/(x(x+1)))=2. 2/5`
`=>1/6+1/12+1/20+...+1/(x(x+1))=2/5`
`=>1/2.3+1/3.4+1/4.5+...+1/(x(x+1))=2/5`
`=>1/2-1/3+1/3-1/4+1/4-1/5+...+1/x-1/(x+1)=2/5`
`=>1/2-1/(x+1)=2/5`
`=>1/(x+1)=1/2-2/5=1/10`
`=>x+1=10`
`=>x=9`