d. (4x-3)(2-3x)-6x(3-2x)= 7+8x
⇒8x-12$x^{2}$ -6+9x-18x+12$x^{2}$ =7+8x
⇒-9x=13
⇒x=$\frac{-13}{9}$
e.x($x^{2}$ -3x+5)-(x+3)(2-x)=$x^{3}$ +$x^{2}$ -6
⇒$x^{3}$ -$3x^{2}+5x-2x+$x^{2}$ -6+3x= $x^{3}$ +$x^{2}$ -6
⇒$-3x^{2}$ +6x=0
⇒-3x(x-2)=0
⇒\(\left[ \begin{array}{l}-3x=0\\x-2=0\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=0\\x=2\end{array} \right.\)
g. 4x(2x-7)-(3x+1)(2x-3)= 3+12x
⇒$8x^{2}$ -28x-$6x^{2}$ +9x-2x+3= 3+12x
⇒$2x^{2}$ -33x=0
⇒x(2x-33)=0
⇒\(\left[ \begin{array}{l}x=0\\2x-33=0\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=0\\x=33/2\end{array} \right.\)