Đáp án:
`A=|x-1/2|`
`⇒|x-1/2|≥0`
Dấu '=" xảy ra khi :
`x-1/2=0`
`⇒x=1/2`
Vậy `GTNN` của `A=0` khi`x=1/2`
$#lam $
Giải thích các bước giải:
`A=|x-\frac{1}{2}|`
$\text{Ta có:}$
`|x-\frac{1}{2}|≥0∀x∈R`
$\text{Dấu '=' xảy ra khi:}$
`|x-\frac{1}{2}|=0`
`⇔x-\frac{1}{2}=0`
`⇔x=\frac{1}{2}`
$\text{Vậy $Min(A)=0$ tại}$ `x=\frac{1}{2}`
Học tốt!!!
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