Bài 2:
a.
Vdd NaOH=200ml=0,2 l
n NaOH=CM.V=2.0,2=0,4 mol
b.
m ct H2SO4=$\frac{mdd.C}{100}$=$\frac{300.9,8}{100}$=29,4 g
n H2SO4=$\frac{m}{M}$=$\frac{29,4}{98}$=0,3 mol
c.
mdd HCl=d.Vdd=1,3.100=130 g
m ct HCl=$\frac{mdd.C}{100}$=$\frac{130.3,65}{100}$=4,745 g
n HCl=$\frac{m}{M}$=$\frac{4,745}{36,5}$=0,13 mol
---------------------Nguyễn Hoạt--------------------
