Giải thích các bước giải:
Ta có:
\(\begin{array}{l}
a,\\
\sqrt {\dfrac{{2x - 3}}{{x - 1}}} = 2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left( {\left[ \begin{array}{l}
x \ge \dfrac{3}{2}\\
x < 1
\end{array} \right.} \right)\\
\Leftrightarrow \dfrac{{2x - 3}}{{x - 1}} = 4\\
\Leftrightarrow 2x - 3 = 4.\left( {x - 1} \right)\\
\Leftrightarrow 2x - 3 = 4x - 4\\
\Leftrightarrow 2x = 1\\
\Leftrightarrow x = \dfrac{1}{2}\,\,\,\,\,\left( {t/m} \right)\\
b,\\
\dfrac{{\sqrt {4x - 3} }}{{\sqrt {x + 1} }} = 3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left( {x \ge \dfrac{3}{4}} \right)\\
\Leftrightarrow \dfrac{{4x - 3}}{{x + 1}} = 3\\
\Leftrightarrow 4x - 3 = 3.\left( {x + 1} \right)\\
\Leftrightarrow 4x - 3 = 3x + 3\\
\Leftrightarrow x = 6\,\,\,\,\,\left( {t/m} \right)
\end{array}\)
