Ta có :
A==$\frac{11× 3^{22}×3^{7}-9^{15}}{(2×3^{14})^{2}}$
=$\frac{11 × 3^{29} - (3^{2}) ^{15} }{2^{2} × 3^{28} }$
=$\frac{11 × 3^{29} - 3^{29} ×3 }{4 × 3^{28} }$
=$\frac{[(11-3)×3^{29} ] }{4 × 3^{28} }$
=$\frac{8×3^{29} }{4 × 3^{28} }$
=$\frac{8×3}{4}$
= 6