Đáp án:
Giải thích các bước giải:
a)$\sqrt[]{3x-1}=4$
$\sqrt[]{(3x-1)^2}=4^2$
$3x-1=16$
$3x=17$
$x=17/3$
b)$\sqrt{x^2-2x+4}=2x-2$
$\sqrt{(x-2)^2}=2x-2$
$x-2=2x-2$
$x=0$
d)$\sqrt[]{4-4\sqrt{x}+x}=3$
$\sqrt[]{(\sqrt{x}-2)^2}=3$
$\sqrt{x}-2=3$
$\sqrt{x}=5$
$x=\sqrt{5}$
e)ko ghi đề
$\sqrt[]{(x-2).(x-1)} -\sqrt{x-1}=0$
$\sqrt{x-1}.(\sqrt[]{x-2} -1)=0$
\(\left[ \begin{array}{l}\sqrt{x-1}=0\\\sqrt[]{x-2} -1=0\end{array} \right.\)
\(\left[ \begin{array}{l}x=1\\x=3\end{array} \right.\)
g)$\sqrt[]{4x^2-4x+1}=\sqrt{x^2-6x+9}$
$\sqrt[]{(2x-1)^2}=\sqrt{(x-3)^2}$
$2x-1=x-3$
$x=-2$
