Đáp án: \(\left[ \begin{array}{l}x=\frac{-1}{12}\\x=\frac{-5}{12}\end{array} \right.\)
Giải thích các bước giải:
| 2x + $\frac{1}{2}$ | = $\frac{1}{3}$
→ \(\left[ \begin{array}{l}2x+\frac{1}{2}=\frac{1}{3}\\2x+\frac{1}{2}=\frac{-1}{3}\end{array} \right.\)
→ \(\left[ \begin{array}{l}2x=\frac{-1}{6}\\2x=\frac{-5}{6}\end{array} \right.\)
→ \(\left[ \begin{array}{l}x=\frac{-1}{12}\\x=\frac{-5}{12}\end{array} \right.\)
