Đáp án:
\(\begin{array}{l}
b.R = 1,5\Omega \\
c.{U_1} = {U_2} = {U_3} = 9V\\
d.l = 352,94m
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
b.\\
\dfrac{1}{R} = \dfrac{1}{{{R_1}}} + \dfrac{1}{{{R_2}}} + \dfrac{1}{{{R_3}}} = \dfrac{1}{3} + \dfrac{1}{4} + \dfrac{1}{{12}} = \dfrac{1}{{1,5}}\\
\Rightarrow R = 1,5\Omega \\
c.\\
{U_1} = {U_2} = {U_3} = {I_1}{R_1} = 3.3 = 9V\\
d.\\
{R_3} = \dfrac{{\rho l}}{S} \Rightarrow l = \dfrac{{S{R_3}}}{\rho } = \dfrac{{0,{{5.10}^{ - 6}}.12}}{{1,{{7.10}^{ - 8}}}} = 352,94m
\end{array}\)