$|x-3|=x-2$
\(\to\left[ \begin{array}{l}x-3=x-2\\x-3=2-x\end{array} \right.\)
\(\to\left[ \begin{array}{l}x-3-x+2=0\\x-3-2+x=0\end{array} \right.\)
\(\to\left[ \begin{array}{l}-1=0(ktm)\\2x-5=0\end{array} \right.\)
$→2x=5$
$→x=\dfrac{5}{2}$
Vậy $x=\Big\{\dfrac{5}{2}\Big\}$