A = 2 + 2² + 2³ + ... + 2⁶⁰
=2+2.2+2.2.2+...+2.2.2.2.2
⇒2 ⋮ 2
Vậy A chia hết cho 2.
A = 2 + 2² + 2³ + ... + 2⁶⁰
=2. (1+2) + 2².(1+2)+ 2³.(1+2)+....+$2^{59}$.(1+2)
=2.3+2².3+ 2³.3+....+$2^{59}$.3⋮ 3
⇒A ⋮ 3
A = 2 + 2² + 2³ + ... + 2⁶⁰
=2. (1+2+4) + 2³.(1+2+4)+ $2^{4}$.(1+2+4)+....+$2^{58}$.(1+2+4)
=2. 7 + 2³.7+ $2^{4}$.7)+....+$2^{58}$.7 ⋮ 7
⇒A⋮ 7