Đáp án:
Bạn tham khảo lời giải ở dưới nhé!!!
Giải thích các bước giải:
\(\begin{array}{l}
Ba{(OH)_2} + 2HCl \to BaC{l_2} + 2{H_2}O\\
B{a^{2 + }} + 2O{H^ - } + 2{H^ + } + 2C{l^ - } \to B{a^{2 + }} + 2C{l^ - } + 2{H_2}O\\
O{H^ - } + {H^ + } \to {H_2}O\\
{H_2}S{O_4} + Mg{(OH)_2} \to MgS{O_4} + 2{H_2}O\\
2{H^ + } + S{O_4}^{2 - } + Mg{(OH)_2} \to M{g^{2 + }} + S{O_4}^{2 - } + 2{H_2}O\\
2{H^ + } + Mg{(OH)_2} \to M{g^{2 + }} + 2{H_2}O\\
3{H_2}S{O_4} + 2Al{(OH)_3} \to A{l_2}{(S{O_4})_3} + 6{H_2}O\\
6{H^ + } + 3S{O_4}^{2 - } + 2Al{(OH)_3} \to 2A{l^{3 + }} + 3S{O_4}^{2 - } + 6{H_2}O\\
3{H^ + } + Al{(OH)_3} \to A{l^{3 + }} + 3{H_2}O\\
BaC{l_2} + N{a_2}S{O_4} \to 2NaCl + BaS{O_4}\\
B{a^{2 + }} + 2C{l^ - } + 2N{a^ + } + S{O_4}^{2 - } \to 2C{l^ - } + 2N{a^ + } + BaS{O_4}\\
B{a^{2 + }} + S{O_4}^{2 - } \to BaS{O_4}\\
3{H_2}S{O_4} + {N_2}{O_3} \to 2NO + {H_3}O + 3HS{O_4}\\
6{H^ + } + 3S{O_4}^{2 - } + {N_2}{O_3} \to 2NO + {H_3}{O^ + } + 3HS{O_4}^ - \\
CaC{O_3} + 2HCl \to CaC{l_2} + C{O_2} + {H_2}O\\
CaC{O_3} + 2{H^ + } + 2C{l^ - } \to C{a^{2 + }} + 2C{l^ - } + C{O_2} + {H_2}O\\
CaC{O_3} + 2{H^ + } \to C{a^{2 + }} + C{O_2} + {H_2}O\\
N{a_2}S{O_3} + 2HCl \to 2NaCl + S{O_2} + {H_2}O\\
2N{a^ + } + S{O_3}^{2 - } + 2{H^ + } + 2C{l^ - } \to 2N{a^ + } + 2C{l^ - } + S{O_2} + {H_2}O\\
S{O_3}^{2 - } + 2{H^ + } \to S{O_2} + {H_2}O\\
{H_2}S{O_4} + ZnO \to ZnS{O_4}c\\
2{H^ + } + S{O_4}^{2 - } + ZnO \to Z{n^{2 + }} + S{O_4}^{2 - } + {H_2}O\\
2{H^ + } + ZnO \to Z{n^{2 + }} + {H_2}O
\end{array}\)
