Đáp án:
Giải thích các bước giải:
$a) (x-6)^{2}=9$
$⇔$\(\left[ \begin{array}{l}x-6=3\\x-6=-3\end{array} \right.\) ⇔\(\left[ \begin{array}{l}x=9\\x=3\end{array} \right.\)
$b) (2x+1)^{3}=125$
$⇔2x+1=5$
$x=2$
$c) 3^{x}+25=26.2^{2}+2.3^{0}$
$⇔3^{x}+25=106$
$⇔3^{x}=81$
$⇔x=4$
$⇔
$d) 2^{x}.4=128$
$⇔2^{x}=32$
$⇔x=5$
$e) x^{15}=x$
$⇔x^{15}-x=0$
$⇔x(x^{14}-1)=0$
$⇔$\(\left[ \begin{array}{l}x=0\\x^{14}=1\end{array} \right.\) ⇔\(\left[ \begin{array}{l}x=0\\x∈1;-1\end{array} \right.\)
