`nZn=0,65:65=0,01 (mol)`
`nHCl= 0,5.0,1=0,05 (mol)`
`Zn + 2HCl -> ZnCl2 + H2`
` 2.nZn < nHCl (0,02 <0,05 )`
` => Zn` hết `; HCl` dư
`a, nZnCl2=nH2 = nZn =0,01 (mol)`
` => mZnCl2 = 0,01.136=1,36 (g)`
` => VH2=0,01.22,4=0,224 (l)`
`b, nHCl pứ = 2.nZn=0,02 (mol)`
`=> nHCl dư =0,05-0,02= 0,03 (mol)`
` => CMHCl dư=0,03:0,5=0,06 (M)`
` nZnCl2=0,01 (mol) => CMZnCl2=0,01:0,5=0,02 (M)`