$n_{CO_2}=\dfrac{1,568}{22,4}=0,07(mol)$
$n_{KOH}=0,5.0,182=0,091(mol)$
$\dfrac{n_{KOH}}{n_{CO_2}}=1,3$
$\Rightarrow$ tạo $KHCO_3$ (x mol), $K_2CO_3$ (y mol)
Bảo toàn K: $x+2y=0,091$ (1)
Bảo toàn C: $x+y=0,07$ (2)
$(1)(2)\Rightarrow x=0,049; y=0,021$
$V_{dd}=0,5l$
$\Rightarrow C_{M_{KHCO_3}}=\dfrac{0,049}{0,5}=0,098M; C_{M_{K_2CO_3}}=\dfrac{0,021}{0,5}=0,042M$
$m_{KHCO_3}=0,049.100=4,9g$
$m_{K_2CO_3}=0,021.138=2,898g$
