Đáp án:
$x=\dfrac{5}{2}$
Giải thích các bước giải:
$|2x-5|+|2x^2-7x+5|=0$
$⇔\left \{ {{2x-5=0} \atop {2x^2-7x+5=0}} \right.$
$⇔\left \{ {{2x=5} \atop {(2x^2-2x)-(5x-5)=0}} \right.$
$⇔\left \{ {{x=\dfrac{5}{2}} \atop {(2x^2-2x)-(5x-5)=0}} \right.$
$⇔\left \{ {{x=\dfrac{5}{2}} \atop {2x.(x-1)-5.(x-1)=0}} \right.$
$⇔\left \{ {{x=\dfrac{5}{2}} \atop {(x-1).(2x-5)=0}} \right.$
$⇔\left \{ {{x=\dfrac{5}{2}} \atop {\left[ \begin{array}{l}x=1\\x=\dfrac{5}{2}\end{array} \right.}} \right.$
$⇔x=\dfrac{5}{2}$