Đáp án:
\( {m_{{C_6}{H_5}N{H_2}}} = 7,46715{\text{ gam}}\)
Giải thích các bước giải:
Phản ứng xảy ra:
\({C_6}{H_5}N{H_2} + 3B{r_2}\xrightarrow{{}}{C_6}{H_2}B{r_3}N{H_3}Br + 2HBr\)
Ta có:
\({n_{{C_6}{H_2}B{r_3}N{H_3}Br}} = \frac{{33}}{{12.6 + 2 + 80.3 + 17 + 80}} = \frac{{11}}{{137}}{\text{ mol = }}{{\text{n}}_{{C_6}{H_5}N{H_2}}}\)
\( \to {m_{{C_6}{H_5}N{H_2}}} = \frac{{11}}{{137}}.(12.6 + 5 + 14 + 2) = 7,46715{\text{ gam}}\)