Em tham khảo nha:
Em xem lại đề chỗ (1) của câu c nhé
\(\begin{array}{l}
a)\\
(1)\,F{e_2}{O_3} + 3CO \xrightarrow{t^0} 2Fe + 3C{O_2}\\
(2)\,C{O_2} + C \to 2CO\\
(3)\,2CO + {O_2} \xrightarrow{t^0} 2C{O_2}\\
(4)\,C{O_2} + NaOH \to NaHC{O_3}\\
(5)\,NaHC{O_3} + NaOH \to N{a_2}C{O_3} + {H_2}O\\
(6)\,N{a_2}C{O_3} + CaC{l_2} \to 2NaCl + CaC{O_3}\\
(7)\,CaC{O_3} \xrightarrow{t^0} CaO + C{O_2}\\
(8)\,CaO + C{O_2} \to CaC{O_3}\\
b)\\
(1)\,HCOOH + {H_2}S{O_4} \to CO + {H_2}S{O_4}.{H_2}O\\
(2)\,2CO + {O_2} \xrightarrow{t^0} 2C{O_2}\\
(3)C{O_2} + 2KOH \to {K_2}C{O_3} + {H_2}O\\
(4){K_2}C{O_3} + C{O_2} + {H_2}O \to 2KHC{O_3}\\
(5)\,KHC{O_3} + KOH \to {K_2}C{O_3} + {H_2}O\\
(6)\,{K_2}C{O_3} + BaC{l_2} \to 2KCl + BaC{O_3}\\
(7)\,BaC{O_3} + C{O_2} + {H_2}O \to Ba{(HC{O_3})_2}\\
(8)\,Ba{(HC{O_3})_2} \to BaC{O_3} + C{O_2} + {H_2}O\\
c)\\
(1)\,\\
(2)\,CO + CuO \xrightarrow{t^0} Cu + C{O_2}\\
(3)3Cu + 8HN{O_3} \to 3Cu{(N{O_3})_2} + 2NO + 4{H_2}O\\
(4)\,2Cu{(N{O_3})_2} \xrightarrow{t^0} 2CuO + 4N{O_2} + {O_2}\\
(5)\,CuO + 2HCl \to CuC{l_2} + {H_2}O\\
(6)\,CuC{l_2} + 2AgN{O_3} \to Cu{(N{O_3})_2} + 2AgCl\\
d)\\
(1)BaC{O_3} \xrightarrow{t^0} BaO + C{O_2}\\
(2)\,C{O_2} + C \to 2CO\\
(3)\,2CO + {O_2} \xrightarrow{t^0} 2C{O_2}\\
(4)\,C{O_2} + Ca{(OH)_2} \to CaC{O_3} + {H_2}O\\
(5)\,CaC{O_3} + 2HCl \to CaC{l_2} + C{O_2} + {H_2}O\\
(6)\,CaC{l_2} + 2AgN{O_3} \to Ca{(N{O_3})_2} + 2AgCl\\
(7)\,Ca{(N{O_3})_2} + N{a_2}C{O_3} \to CaC{O_3} + 2NaN{O_3}\\
(8)\,CaC{O_3} \xrightarrow{t^0} CaO + C{O_2}
\end{array}\)
