a) đkxđ: `x≥5`
`\sqrt(x-5)=3`
`⇔x-5=9`
`⇔x=14`
b) đkxđ: `x≥2`
`\sqrt(9x-18)+2\sqrt(25x-50)-3\sqrt(4x-8)=4`
`⇔3\sqrt(x-2)+5\sqrt(x-2)-6\sqrt(x-2)=4`
`⇔2\sqrt(x-2)=4`
`⇔\sqrt(x-2)=2`
`⇔x-2=4`
`⇔x=6`
Vậy `x=6`
c) đkxđ: $x∈\Bbb R$
`\sqrt(x^2+10x+25)=3`
`⇔\sqrt[(x+5)^2]=3`
`⇔|x+5|=3`
`⇔x+5=3`
`⇔x=-2`
Vậy `x=-2`