Em tham khảo nha:
\(\begin{array}{l}
3)\\
a)\\
{N_{Na}} = n \times 6 \times {10^{23}} = 0,8 \times 6 \times {10^{23}} = 4,8 \times {10^{23}}\\
b)\\
{n_{N{O_2}}} = \dfrac{V}{{22,4}} = \dfrac{{2,24}}{{22,4}} = 0,1\,mol\\
{N_{N{O_2}}} = n \times 6 \times {10^{23}} = 0,1 \times 6 \times {10^{23}} = 6 \times {10^{22}}\\
c)\\
{n_{NO}} = \dfrac{V}{{24}} = \dfrac{{7,2}}{{24}} = 0,3\,mol\\
{N_{NO}} = n \times 6 \times {10^{23}} = 0,3 \times 6 \times {10^{23}} = 1,8 \times {10^{23}}\\
d)\\
{n_{F{e_2}{O_3}}} = \dfrac{m}{M} = \dfrac{{16}}{{160}} = 0,1\,mol\\
{N_{F{e_2}{O_3}}} = n \times 6 \times {10^{23}} = 0,1 \times 6 \times {10^{23}} = 6 \times {10^{22}}\\
e)\\
{n_{CO}} = \dfrac{V}{{22,4}} = \dfrac{{5,6}}{{22,4}} = 0,25\,mol\\
{n_{C{O_2}}} = \dfrac{V}{{22,4}} = \dfrac{{2,24}}{{22,4}} = 0,1\,mol\\
{N_{hh}} = n \times 6 \times {10^{23}} = (0,25 + 0,1) \times 6 \times {10^{23}} = 2,1 \times {10^{23}}\\
g)\\
{n_{{H_2}}} = \dfrac{V}{{24}} = \dfrac{{4,8}}{{24}} = 0,2\,mol\\
{n_{{H_2}S}} = \dfrac{V}{{24}} = \dfrac{{2,4}}{{24}} = 0,1\,mol\\
{N_{hh}} = n \times 6 \times {10^{23}} = (0,2 + 0,1) \times 6 \times {10^{23}} = 1,8 \times {10^{23}}\\
h)\\
{n_{C{O_2}}} = \dfrac{m}{M} = \dfrac{{4,4}}{{44}} = 0,1\,mol\\
{n_{S{O_2}}} = \dfrac{m}{M} = \dfrac{8}{{80}} = 0,1\,mol\\
{N_{hh}} = (0,1 + 0,1) \times 6 \times {10^{23}} = 1,2 \times {10^{23}}\\
4)\\
a)\\
{m_{{C_6}{H_{12}}{O_6}}} = n \times M = 0,7 \times 180 = 126g\\
b)\\
{n_{KMn{O_4}}} = \dfrac{{0,9 \times {{10}^{23}}}}{{6 \times {{10}^{23}}}} = 0,15\,mol\\
{m_{KMn{O_4}}} = n \times M = 0,15 \times 158 = 23,7g\\
c)\\
{n_{S{O_3}}} = \dfrac{V}{{22,4}} = \frac{{8,96}}{{22,4}} = 0,4\,mol\\
{m_{S{O_3}}} = n \times M = 0,4 \times 80 = 32g\\
d)\\
{n_{CuO}} = \dfrac{{0,12 \times {{10}^{23}}}}{{6 \times {{10}^{23}}}} = 0,02\,mol\\
{n_{FeO}} = \dfrac{{0,18 \times {{10}^{23}}}}{{6 \times {{10}^{23}}}} = 0,03\,mol\\
{m_{hh}} = 0,02 \times 80 + 0,03 \times 72 = 3,76g\\
e)\\
{n_{{N_2}O}} = \dfrac{V}{{24}} = \dfrac{{2,4}}{{24}} = 0,1\,mol\\
{n_{N{O_2}}} = \dfrac{V}{{24}} = \dfrac{{4,8}}{{24}} = 0,2\,mol\\
{m_{hh}} = 0,1 \times 44 + 0,2 \times 46 = 13,6g
\end{array}\)
