$\overrightarrow{AB} = (-4m;-3m -3)$
$\overrightarrow{AC} = (- m-5; 1- 2m)$
$A,\, B,\, C$ thẳng hàng $\overrightarrow{AB}= k.\overrightarrow{AC}$
$\to \dfrac{-4m}{-m-5} =\dfrac{-3m -3}{1-2m} = k$
$\to \dfrac{4m}{m+5}=\dfrac{3m+3}{2m-1}$
$\to 4m(2m-1) = (3m+3)(m+5)$
$\to 8m^2 - 4m = 3m^2 + 15m + 3m + 15$
$\to 5m^2 - 22m - 15 = 0$
$\to \left[\begin{array}{l}m =5\\m =-\dfrac35\end{array}\right.$