\(\left(x-\dfrac{1}{5}\right)\left(2x+\dfrac{3}{4}\right)=0\) \(\Rightarrow x-\dfrac{1}{5}=0\) hoặc \(2x+\dfrac{3}{4}=0\) \(x=0+\dfrac{1}{5}\) hoặc \(2x=0-\dfrac{3}{4}\) \(x=\dfrac{1}{5}\) hoặc \(2x=-\dfrac{3}{4}\) \(x=\dfrac{1}{5}\) hoặc \(x=-\dfrac{3}{4}:2\) \(x=\dfrac{1}{5}\) hoặc \(x=-\dfrac{3}{8}\)"
Vậy x =\(\dfrac{1}{5}\veebar x=-\dfrac{3}{8}\) ~~ học tốt~~