Đáp án:
C M NaCl = C M NaClO = 1 , 6 M {C_{M{\text{ NaCl}}}} = {C_{M{\text{ NaClO}}}} = 1,6M C M NaCl = C M NaClO = 1 , 6 M
C M NaOH = 0 , 8 M {C_{M{\text{ NaOH}}}} = 0,8M C M NaOH = 0 , 8 M
Giải thích các bước giải:
Phản ứng xảy ra:
M n O 2 + 4 H C l → M n C l 2 + C l 2 + 2 H 2 O Mn{O_2} + 4HCl\xrightarrow{{}}MnC{l_2} + C{l_2} + 2{H_2}O M n O 2 + 4 H C l M n C l 2 + C l 2 + 2 H 2 O
Ta có:
n M n O 2 = 69 , 9 55 + 16.2 = 0 , 8 mol {n_{Mn{O_2}}} = \frac{{69,9}}{{55 + 16.2}} = 0,8{\text{ mol}} n M n O 2 = 5 5 + 1 6 . 2 6 9 , 9 = 0 , 8 mol
→ n C l 2 = n M g C l 2 = 0 , 8 mol \to {n_{C{l_2}}} = {n_{MgC{l_2}}} = 0,8{\text{ mol}} → n C l 2 = n M g C l 2 = 0 , 8 mol
n N a O H = 0 , 5.4 = 2 mol > 2 n C l 2 {n_{NaOH}} = 0,5.4 = 2{\text{ mol > 2}}{{\text{n}}_{C{l_2}}} n N a O H = 0 , 5 . 4 = 2 mol > 2 n C l 2
Do vậy N a O H NaOH N a O H
2 N a O H + C l 2 → N a C l + N a C l O + H 2 O 2NaOH + C{l_2}\xrightarrow{{}}NaCl + NaClO + {H_2}O 2 N a O H + C l 2 N a C l + N a C l O + H 2 O
→ n N a C l = n N a C l O = n C l 2 = 0 , 8 mol \to {n_{NaCl}} = {n_{NaClO}} = {n_{C{l_2}}} = 0,8{\text{ mol}} → n N a C l = n N a C l O = n C l 2 = 0 , 8 mol
n N a O H = 2 − 0 , 8.2 = 0 , 4 mol {n_{NaOH}} = 2 - 0,8.2 = 0,4{\text{ mol}} n N a O H = 2 − 0 , 8 . 2 = 0 , 4 mol
→ C M NaCl = C M NaClO = 0 , 8 0 , 5 = 1 , 6 M \to {C_{M{\text{ NaCl}}}} = {C_{M{\text{ NaClO}}}} = \frac{{0,8}}{{0,5}} = 1,6M → C M NaCl = C M NaClO = 0 , 5 0 , 8 = 1 , 6 M
C M NaOH = 0 , 4 0 , 5 = 0 , 8 M {C_{M{\text{ NaOH}}}} = \frac{{0,4}}{{0,5}} = 0,8M C M NaOH = 0 , 5 0 , 4 = 0 , 8 M
