$\begin{array}{l}A = 2^0 + 2^1 + 2^2 + \dots + 2^{2010}\\ \to 2A = 2^1 + 2^2 + 2^3 + \dots +2^{2011}\\ \to 2A - A = (2^1 + 2^2 + 2^3 + \dots +2^{2011}) - (2^0 + 2^1 + 2^2 + \dots +2^{2010})\\ \to A = 2^{2011} - 2^0\\ \to A = 2^{2011} - 1\\ \to A = B\\ Với\,\,B = 2^{2011} - 1 \end{array}$