Đáp án:
\(\begin{array}{l}
b)\\
CTHH:{C_{20}}{H_{14}}{O_4}\\
c)\\
CTHH:{C_{10}}{H_{16}}
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
b)\\
CTHH:{C_x}{H_y}{O_z}\\
\% C = \dfrac{{x{M_C}}}{M} \times 100\% = 75,47\% \\
\Rightarrow x = \dfrac{{0,7547 \times 318}}{{12}} = 20\\
\% H = \dfrac{{y{M_H}}}{M} \times 100\% = 4,35\% \\
\Rightarrow y = \dfrac{{0,0435 \times 318}}{1} = 14\\
20{M_C} + 14{M_H} + z{M_O} = 318\\
\Rightarrow z = \dfrac{{318 - 20 \times 12 - 14}}{{16}} = 4\\
\Rightarrow CTHH:{C_{20}}{H_{14}}{O_4}\\
c)\\
CTHH:{C_x}{H_y}\\
M = 4,69{M_{kk}} = 4,69 \times 29 = 136dvC\\
\% C = \dfrac{{x{M_C}}}{M} \times 100\% = 88,235\% \\
\Rightarrow x = \dfrac{{0,88235 \times 136}}{{12}} = 10\\
10{M_C} + y{M_H} = 136\\
\Rightarrow y = 136 - 10 \times 12 = 16\\
\Rightarrow CTHH:{C_{10}}{H_{16}}
\end{array}\)
