Đáp án:
Giải thích các bước giải:
`\frac{2x-\frac{4-3x}{5}}{15}=\frac{7x-\frac{x-3}{2}}{5}-x+1`
`⇔ \frac{\frac{10x-4+3x}{5}}{15}=\frac{\frac{14x-x+3}{2}}{5}-\frac{5(x-1)}{5}`
`⇔ \frac{\frac{13x-4}{5}}{15}=\frac{\frac{13x+3}{2}-\frac{2(5x-5)}{2}}{5}`
`⇔ \frac{\frac{13x-4}{5}}{15}=\frac{\frac{3x+13}{2}}{5}`
`⇔ \frac{5(13x-4)}{5}=\frac{15(3x+13)}{2}`
`⇔ 10(13x-4)=75(3x+13)`
`⇔ 130x-40=225x+975`
`⇔ x=-\frac{203}{19}`
Vậy `S={-\frac{203}{19}}`
