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tinntunn4ever
2 năm trước
Cho lăng trụ đứng $ABC.A’B’C'$ có $AB = 6, BC = 12,$ $\widehat{ABC} = 60^0$. Thể tích khối chóp $C’.ABB’A’$ bằng $216$. Gọi $M$ là điểm nằm trong tam giác $A’B’C’$ sao cho tổng diện tích các mặt bên của hình chóp $M.ABC$ đạt $GTNN$. Tính cosin góc giữa hai đường thẳng $B’M$ và $AC’$ ?
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