$\text{Ta có:} 1m^3=1000dm^3=1000(l)$
$\to V_{CH_4\text{..không tạp}}=1000.\dfrac{100-2}{100}=980(l)$
$\to n_{CH_4}=\frac{980}{22,4}=43,75(mol)$
$\text{PTHH:}$
$CH_4 + 2O_2 \xrightarrow{t^0} CO_2 +2H_2O$
$\text{Do:} n_{O_2}=2n_{CH_4}=2.43,75=87,5(mol)$
$\to V_{O_2}=87,5.22,4=1960(l)$
$#@skiinchee00$