Đáp án:
\(CTPT:{C_6}{H_{12}}{O_6}\)
Giải thích các bước giải:
\(\begin{array}{l}
{M_A} = 5,625{M_{{O_2}}} = 180dvC\\
{n_A} = \dfrac{{1,8}}{{180}} = 0,01mol\\
{n_{C{O_2}}} = \dfrac{{1,344}}{{22,4}} = 0,06mol\\
{n_{{H_2}O}} = \dfrac{{1,08}}{{18}} = 0,06mol\\
{n_C} = {n_{C{O_2}}} = 0,06mol\\
{n_H} = 2{n_{{H_2}O}} = 0,12mol\\
CTPT:{C_x}{H_y}{O_z}\\
x = \dfrac{{{n_C}}}{{{n_A}}} = \dfrac{{0,06}}{{0,01}} = 6\\
y = \dfrac{{{n_H}}}{{{n_A}}} = \dfrac{{0,12}}{{0,01}} = 12\\
z = \dfrac{{180 - 6 \times 12 - 12}}{6} = 6\\
\Rightarrow CTPT:{C_6}{H_{12}}{O_6}
\end{array}\)
