Đáp án:
Giải thích các bước giải:
`-3/2 x^2+x+1/2=0`
`⇔-3/2 .(x^2-2/3 x)+1/2=0`
`⇔-3/2 .(x^2-2/3 x+1/9)+1/2+1/6=0`
`⇔-3/2 .(x-1/3)^2=-2/3`
`⇔(x-1/3)^2=4/9`
`⇔`\(\left[ \begin{array}{l}x-\dfrac{1}{3}=\dfrac{2}{3}\\x-\dfrac{1}{3}=-\dfrac{2}{3}\end{array} \right.\)
`⇔`\(\left[ \begin{array}{l}x=1\\x=-\dfrac{1}{3}\end{array} \right.\)