Đáp án: $\text{A: $Cl_2$}$
$\text{B: $MnCl_2$}$
$\text{C: $H_2O$}$
$\text{D: HCl}$
$\text{E: $O_2$}$
$\text{F: $H_2$}$
$\text{G: $CaCl_2$}$
Giải thích các bước giải:
1) $4HCl_{đ}+MnO_2$ $\buildrel{{t^o}}\over\longrightarrow Cl_2↑+MnCl_2+2H_2O$
2) $3Cl_2+2Fe\buildrel{{t^o}}\over\longrightarrow 2FeCl_3$
3) $2Cl_2+2H_2O\buildrel{{á/s}}\over\longrightarrow 4HCl+O_2↑$
4) $2HCl +Ca(OH)_2\buildrel{{}}\over\longrightarrow CaCl_2+2H_2O$
5) $2H_{2}+O_2$ $\buildrel{{t^o}}\over\longrightarrow 2H_2O$
6) $H_2+Cl_2\buildrel{{t^o}}\over\longrightarrow 2HCl$
