Đáp án :
`+)x∈{7; 15}`
`+)x∈{7/5; 3}`
Giải thích các bước giải :
`+)|x-11|(-6)=-|-24|`
`<=>|x-11|(-6)=-24`
`<=>|x-11|=(-24):(-6)`
`<=>|x-11|=4`
`<=>`\(\left[ \begin{array}{l}x-11=-4\\x-11=4\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=7\\x=15\end{array} \right.\)
Vậy `x∈{7; 15}`
`+)|5x-11|(-8)=-|-32|`
`<=>|5x-11|(-8)=-32`
`<=>|5x-11|=(-32):(-8)`
`<=>|5x-11|=4`
`<=>`\(\left[ \begin{array}{l}5x-11=-4\\5x-11=4\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}5x=7\\5x=15\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=\frac{7}{5}\\x=3\end{array} \right.\)
Vậy `x∈{7/5; 3}`
