Sửa đề:
c) $\frac{1}{2}$ + $\frac{-3}{5}$ + $\frac{1}{10}$ < x < $\frac{8}{3}$ + $\frac{14}{6}$
$\frac{1}{2}$ + $\frac{-6}{10}$ + $\frac{1}{10}$ < x < $\frac{16}{6}$ + $\frac{14}{6}$
$\frac{1}{2}$ + $\frac{-5}{10}$ < x < $\frac{16+14}{6}$
$\frac{1}{2}$ + $\frac{-1}{2}$ < x < $\frac{30}{6}$
0 < x < 5.
Vậy x = {1,2,3,4}.