Đáp án:
`\text{Em tham khảo!}`
Giải thích các bước giải:
`b,2x-1=0`
`<=>2x=1`
`<=>x=1/2`
`3x-(8-x)=0`
`<=>3x+x-8=0`
`<=>4x-8=0`
`<=>x-2=0`
`<=>x=2`
`c,x+1=0`
`<=>x=-1`
`(x+1)(x+2)=0`
`<=>` \(\left[ \begin{array}{l}x+1=0\\x+2=0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=-2\\x=-1\end{array} \right.\)
`(2x^3-1)/(2x)=(5x-1)/(2x)(x ne 0)`
`<=>2x^3-1=5x-1`
`<=>2x^3=5x`
`<=>x(2x^2-5)=0`
`<=>` \(\left[ \begin{array}{l}x=0(loại)\\2x^2=5\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x^2=\dfrac{5}{2}\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=\sqrt{\dfrac{5}{2}}\\x=-\sqrt{\dfrac{5}{2}}\end{array} \right.\)
`(x^2-5x)/(2x)=0(x ne 0)`
`<=>(x(x-5))/(2x)=0`
`<=>(x-5)/2=0`
`<=>x-5=0`
`<=>x=5(TM)`