Đáp án:
Giải thích các bước giải:
ta có:
a)(x-1)($x^{2}$+3x-2)-($x^{3}$-1)=0
⇔(x-1)($x^{2}$+3x-2)-(x-1)($x^{2}$+x+1)=0
⇔(x-1)($x^{2}$-$x^{2}$+3x-2-x-1)=0
⇔(x-1)(2x-3)=0
⇔\(\left[ \begin{array}{l}x-1=0\\2x-3=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=1\\x=$\frac{3}{2}$ \end{array} \right.\)
b,($x^{2}$+$x^{2}$)+($x^{2}$ +x)=0
⇔$x^{2}$(x+1)+x(x+1)=0
⇔(x+1)($x^{2}$ +x)=0
⇔x(x+1)^2=0
⇔\(\left[ \begin{array}{l}x=0\\x+1=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=0\\x=-1\end{array} \right.\)
