Bài 1:
`a)` `\frac{x+4}{2}-\frac{x-1}{3}=1`
`\to 3(x+4)-2(x-1)-2.3=0`
`\to 3x+12-2x+2-6=0`
`\to x-8=0`
`\to x=8`
Vậy `S={8}`
`b)` `(x-2)^2=9`
`\to (x-2)^2-9=0`
`\to (x-2-3)(x-2+3)=0`
`\to (x-5)(x+1)=0`
$\to \begin{cases}x-5=0\\ x+1=0\\\end{cases} \to \begin{cases} x=5\\ x= -1\\\end{cases}$
Vậy `S={-1;5}`
`c)` `(x+4)^2+(3+x)(3-x)=1`
`\to x^2+8x+16+9-x^2-1=0`
`\to 8x+24=0`
`\to x=-3`
Vậy `S={-3}`
`d)` `\frac{5x+3}{6}+1=\frac{5x+1}{3}`
`\to 5x+3+6-2(5x+1)=0`
`\to 5x+9-10x-2=0`
`\to -5x+7=0`
`\to x=\frac{7}{5}`
Vậy `S={\frac{7}{5}}`
`e)` `\frac{x-5}{4}-\frac{-2x+2}{3}=\frac{1-x}{2}`
`\to 3(x-5)-4(2-2x)-6(1-x)=0`
`\to 3x-15-8+8x-6+6x=0`
`\to17x-29=0`
`\to x=\frac{29}{17}`
Vậy `S={\frac{29}{17}}`
`g)` `x^2+5x+6=0`
`\to x^2+2x+3x+6=0`
`\to x(x+2)+3(x+2)=0`
`\to (x+2)(x+3)=0`
$\to$ \(\left[ \begin{array}{l}x+2=0\\x+3=0\end{array} \right.\) $\to$\(\left[ \begin{array}{l}x=-2\\x=-3\end{array} \right.\)
Vậy `S={-2;-3}`
`h)` `4(x-2)=2x+10`
`\to 4x-8-2x-10=0`
`\to 2x-18=0`
`\to x=9`
Vậy `S={9}`
