Em tham khảo nha:
\(\begin{array}{l}
{n_{C{O_2}}} = \dfrac{{2,2}}{{44}} = 0,05mol\\
{n_{{O_2}}} = \dfrac{{16}}{{32}} = 0,5\,mol\\
{n_{{N_2}}} = \dfrac{4}{{28}} = \frac{1}{7}mol\\
\% {V_{C{O_2}}} = \dfrac{{0,05}}{{0,05 + 0,5 + \dfrac{1}{7}}} \times 100\% = 7,22\% \\
\% {V_{{O_2}}} = \dfrac{{0,5}}{{0,05 + 0,5 + \dfrac{1}{7}}} \times 100\% = 72,16\% \\
\% {V_{{N_2}}} = 100 - 72,16 - 7,22 = 20,62\% \\
\% {m_{{O_2}}} = \dfrac{{16}}{{2,2 + 16 + 4}} \times 100\% = 72,07\% \\
\% {m_{C{O_2}}} = \dfrac{{2,2}}{{2,2 + 16 + 4}} \times 100\% = 9,91\% \\
\% {m_{{N_2}}} = 100 - 9,91 - 72,07 = 18,02\%
\end{array}\)
