Em tham khảo nha :
\(\begin{array}{l}
a)\\
{C_n}{H_{2n + 2}} + \frac{{3n - 1}}{2}{O_2} \to nC{O_2} + (n - 1){H_2}O\\
{n_{C{O_2}}} = \dfrac{{17,6}}{{44}} = 0,4mol\\
{n_X} = \dfrac{{5,8}}{{14n + 2}}mol\\
{n_{C{O_2}}} = n \times {n_X}\\
\Rightarrow 0,4 = n \times \frac{{5,8}}{{14n + 2}}\\
\Rightarrow n = 4\\
\Rightarrow CTPT:{C_4}{H_{10}}\\
b)\\
C{H_3} - C{H_2} - C{H_2} - C{H_3}(Bu\tan )\\
C{H_3} - CH(C{H_3}) - C{H_3}(2 - metylpropan)
\end{array}\)