a,
$CH_2=CH-CH=CH_2+HBr\xrightarrow{{ -80^oC, 1:1}} CH_3-CHBr-CH=CH_2$ (spc)
$CH_2=CH-CH=CH_2+HBr\xrightarrow{{-80^oC, 1:1}} CH_2Br-CH_2-CH=CH_2$ (spp)
b,
$CH_3-C(CH_3)=CH-CH_3+HBr\longrightarrow CH_3-CBr(CH_3)-CH_2-CH_3$ (spc)
$CH_3-C(CH_3)=CH-CH_3+HBr\longrightarrow CH_3-CH(CH_3)-CHBr-CH_3$ (spp)
c,
$CH_3-C\equiv C-CH_3+AgNO_3+NH_3 \not\to$ (không phản ứng)
d,
Dẫn hỗn hợp qua nước brom dư. Sau khi phản ứng kết thúc, khí bay ra là metan.
$C_2H_2+2Br_2\to Br_2CH-CHBr_2$
$C_2H_4+Br_2\to BrCH_2-CH_2Br$