Đáp án:
a) 1 lít
b) 70 lít
Giải thích các bước giải:
a)
$\begin{gathered}
{n_{{C_2}{H_2}}} = \dfrac{{5,6}}{{22,4}} = 0,25{\text{ mol}} \hfill \\
{\text{PTHH: }}{{\text{C}}_2}{H_2} + 2B{r_2} \to {C_2}{H_2}B{r_4} \hfill \\
\Rightarrow {n_{B{r_2}}} = 2{n_{{C_2}{H_2}}} = 0,5{\text{ mol}} \hfill \\
\Rightarrow {V_{{\text{dd}}B{r_2}}} = \dfrac{n}{{{C_M}}} = \dfrac{{0,5}}{{0,5}} = 1\left( l \right) \hfill \\
\end{gathered} $
b)
$\begin{gathered}
{C_2}{H_2} + \dfrac{5}{2}{O_2}\xrightarrow{{{t^o}}}2C{O_2} + {H_2}O \hfill \\
\Rightarrow {n_{{O_2}}} = \dfrac{5}{2}{n_{{C_2}{H_2}}} = \dfrac{5}{2}.0,25 = 0,625{\text{ mol}} \hfill \\
\Rightarrow {{\text{V}}_{kk}} = 5{V_{{O_2}}} = 5.0,625.22,4 = 70\left( l \right) \hfill \\
\end{gathered} $
