Đáp án+Giải thích các bước giải:
`a)`
`-2/3.x+1/5=3/10`
`\to-2/3x=3/10-1/5`
`\to-2/3x=1/10`
`\tox=1/10:-2/3`
`\tox=-3/20`
Vậy `x=-3/20`
`b)`
`|x|-3/4=5/3`
`\to|x|=5/3+3/4`
`\to|x|=29/12`
`\to` \(\left[ \begin{array}{l}x=\dfrac{29}{12}\\x=-\dfrac{29}{12}\end{array} \right.\)
Vậy `x\in{29/12;-29/12}`
`c)`
`2/5+3/5.(x-1)=1/10`
`\to3/5(x-1)=1/10-2/5`
`\to3/5(x-1)=-3/10`
`\tox-1=-3/10:3/5`
`\tox-1=-1/2`
`\tox=1/2`
Vậy `x=1/2`
