Đáp án+Giải thích các bước giải:
$\\\text{Ta có: 4 + 5 + a + 2 + 5 + 6 + b + 2=40}\\=>24+a+b=40\\=>a+b=16\\=>b=16-a\\\overline{X}=\dfrac{3. 4+4. 5+5a+6. 2+7. 5+8. 6+ 9. b+10. 2}{40}=6,275\\\overline{X}=\dfrac{5a+9b+147}{40}=6,275\\=>5a+9b+147=6,275.40\\=>5a+9b+147=251\\=>5a+9.(16-a)=251-147\\5a+144-9a=104\\=>-4a+144=104\\=>-4a=104-144\\=>-4a=-40\\=>a=(-40):(-4)\\=>a=10\\+)b=16-a=16-10=6$