Tính bằng cách hợp lí (nếu có thể) :
\(\begin{array}{*{20}{l}}{A = \left( {6888:56-{{11}^2}} \right).152 + 13.72 + 13.28}\\{B = \left[ {5082:\left( {{{17}^{29}}:{{17}^{27}}-{{16}^2}} \right) + 13.12} \right]:31 + {9^2}}\end{array}\)
A.\(A=1604\)
\(B=91\)
B.\(A=1605\)
\(B=90\)
C.\(A=1624\)
\(B=19\)
D.\(A=6104\)
\(B=18\)
\(\begin{array}{*{20}{l}}{A = \left( {6888:56-{{11}^2}} \right).152 + 13.72 + 13.28}\\{B = \left[ {5082:\left( {{{17}^{29}}:{{17}^{27}}-{{16}^2}} \right) + 13.12} \right]:31 + {9^2}}\end{array}\)
A.\(A=1604\)
\(B=91\)
B.\(A=1605\)
\(B=90\)
C.\(A=1624\)
\(B=19\)
D.\(A=6104\)
\(B=18\)
Loga
Hóa Học lớp 12
