$\rm\ n_{C_6H_{12}O_6}=\dfrac{200.0,18}{180}=0,2(mol)$
Phương trình:
$\rm\ C_6H_{12}O_6+ Ag_2O\overset{AgNO_3/ \ NH_3, \ \ t^o}{\to} 2Ag+C_6H_{12}O_7 $
`=> ` $\rm \ n_{Ag}=2n_{C_6H_{12}O_6}=0,4(mol)$
`=> `$\rm \ m_{Ag}=0,4.108=43,2g$
Bảo toàn $\rm \ Ag$
`=>` $\rm \ n_{AgNO_3}=2n_{Ag_2O}=0,4(mol)$
`=>` $\rm \ m_{AgNO_3}=0,4.170=68g$