Giải thích các bước giải:
PTHH:
$CH_4+Cl_2\xrightarrow{as}CH_3Cl+HCl$
$CH\equiv CH+2Br_2\to CHBr_2-CH_2Br_2$
$nCH_2=CH_2\xrightarrow{t^\circ,xt,p}(\kern-6pt-CH_2-CH_2-\kern-6pt)_n$
$2CH\equiv CH+5O_2\xrightarrow{t^\circ} 4CO_2+2H_2O$
$CaC_2+2H_2O\to Ca(OH)_2+CH\equiv CH$