Đáp án:
Giải thích các bước giải:
\(a,\ (2x+1):(5-3x)=4:5\\ ⇔5(2x+1)=4(5-3x)\\ ⇔10x+5=20-12x\\ ⇔10x+12x=20-5\\ ⇔22x=15\\ ⇔x=\dfrac{15}{22}\\ \text{Vậy x = $\dfrac{15}{22}$}\\ b,\ -3:(5x+1)=2:(-3x+2)\\ ⇔-3(-3x+2)=2(5x+1)\\ ⇔9x-6=10x+2\\ ⇔9x-10x=2+6\\ ⇔-x=8\\ ⇔x=(-8)\\ \text{Vậy x = (- 8)}\\ c,\ (2x-3)^3:(-32)=(-2):(2x-3)^3\\ ⇔(2x-3)^6=64\\ ⇔(2x-3)^6=(±2)^6\\ ⇔\left[ \begin{array}{l}2x-3=2\\2x-3=-2\end{array} \right.\\ ⇔\left[ \begin{array}{l}x=\dfrac{5}{2}\\x=\dfrac{1}{2}\end{array} \right.\\ \text{Vậy x = $\dfrac{5}{2}$ hoặc x = $\dfrac{1}{2}$}\)
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