Đáp án:
$\begin{array}{l}
2\sin 3x - \sqrt 3 = 0\\
\Rightarrow \sin 3x = \frac{{\sqrt 3 }}{2}\\
\Rightarrow \left[ \begin{array}{l}
3x = \frac{\pi }{3} + k2\pi \\
3x = \pi - \frac{\pi }{3} + k2\pi
\end{array} \right.\\
\Rightarrow \left[ \begin{array}{l}
x = \frac{\pi }{9} + \frac{{k2\pi }}{3}\\
x = \frac{{2\pi }}{9} + \frac{{k2\pi }}{3}
\end{array} \right.
\end{array}$
