$$$\left|7x-5y\right|+ \left|2z-3x\right|=0$

$\left\{{}\begin{matrix}\left|7x-5y\right|\ge0\\\left|2z-3x\right|\ge0\end{matrix}\right.$

$\Rightarrow\left|7x-5y\right|+\left|2z-3x\right|\ge0$

Dấu "=" xảy ra khi:

$\left\{{}\begin{matrix}\left|7x-5y\right|=0\Rightarrow7x=5y\\\left|2z-3x\right|=0\Rightarrow2z=3x\end{matrix}\right.$

$\Rightarrow\left\{{}\begin{matrix}\dfrac{x}{5}=\dfrac{y}{7}\\\dfrac{z}{3}=\dfrac{x}{2}\end{matrix}\right.$

$\Rightarrow\dfrac{x}{10}=\dfrac{y}{2}=\dfrac{z}{15}$

Đặt:

$\dfrac{x}{10}=\dfrac{y}{2}=\dfrac{z}{15}=k$

$\Rightarrow\left\{{}\begin{matrix}x=10k\\y=2k\\z=15k\end{matrix}\right.$

Thay vào biểu thức ta có:(đã sửa đề)
$10k.2k+2k.15k+10k.15k=2000$

$\Rightarrow20k^2+30k^2+150k^2=2000$

$\Rightarrow200k^2=2000$

$\Rightarrow k^2=10\Rightarrow k=\pm\sqrt{10}$

$\Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x=10\sqrt{10}\\y=2\sqrt{10}\\z=15\sqrt{10}\end{matrix}\right.\\\left\{{}\begin{matrix}x=-10\sqrt{10}\\y=-2\sqrt{10}\\z=-15\sqrt{10}\end{matrix}\right.\end{matrix}\right.$